You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Example 1:
Input: 2 Output: 2 Explanation: There are two ways to climb to the top. 1. 1 step + 1 step 2. 2 steps
Example 2:
Input: 3 Output: 3 Explanation: There are three ways to climb to the top. 1. 1 step + 1 step + 1 step 2. 1 step + 2 steps 3. 2 steps + 1 step
Constraints:
1 <= n <= 45
Solution:
public int climbStairs(int n) {
if(n == 0){
return 0;
}else if(n ==1){
return 1;
}else if(n == 2){
return 2;
}
int[] dp = new int[n+1];
dp[1] = 1;
dp[2] = 2;
for (int i = 3; i <= n; i++){
dp[i] = dp[i-1]+dp[i-2];
}
return dp[n];
}